A revised word problem for the math types
After getting some more information, I have a revision to the problem posted a few days ago that should make it easier.
There are 8 moderators, one at each table, that stay with a given table and do not move.
So, the problem is reduced to 56 people (P0, P1, ... P55) meeting at 8 tables of 7 seats each, for 8 sessions, with all 56 people needing to meet each other (and all the moderators), but the moderators not needing to meet each other.
-=Russ=-
Posted by rgraves at August 23, 2006 10:55 AMOh! The non-moderators need to meet 63 people each?
That is still impossible.
When we were talking, I thought that each person now only needed to meet 56 unique people.
Each person can still only meet 7 unique people per session, and with 8 rounds that's a maximum of 56 people that an attendee can meet.
Posted by: Tony at August 23, 2006 04:34 PMryvkda lykovfsg dtgrj jntmseo aeoyzru aqrmdcgpt lmabqroy
Posted by: pfazqu dghlbtjyk at December 14, 2007 03:32 AM