A word problem for all you math people out there.
64 people (P0, P1, P2, ... P63) are going to be attending a Speed Networking event. There are 8 tables of 8 people each.
Find a way to arrange 8 sessions such that everyone has a chance to network with everyone else, with a minimum of duplication at each point (so you're not sitting with the same people more often than needed).
-=Russ=-
Posted by rgraves at August 21, 2006 11:10 AMya know, i'm sure there's a simple solution to this one and the complexity of my pseudo-solution will be astounding...nevertheless, two words, "brute force". "why not put our pentiums to work, O(n^8) style", says the lazy programmer.
Not possible.
If each person can sit with seven unique people during each of the eight sessions, that is only 56 of the 63 people that they need to sit with.
Posted by: Tony at August 22, 2006 11:06 AMuhh, good point. but i suppose my program could have told me that too :)
Posted by: erik at August 22, 2006 01:39 PM